1404424411431 has 4 divisors (see below), whose sum is σ = 1872565881912. Its totient is φ = 936282940952.

The previous prime is 1404424411399. The next prime is 1404424411471. The reversal of 1404424411431 is 1341144244041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1404424411431 - 2⁵ = 1404424411399 is a prime.

It is a super-2 number, since 2×1404424411431² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1404424411392 and 1404424411401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1404424411471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 234070735236 + ... + 234070735241.

It is an arithmetic number, because the mean of its divisors is an integer number (468141470478).

Almost surely, 2^{1404424411431} is an apocalyptic number.

1404424411431 is a deficient number, since it is larger than the sum of its proper divisors (468141470481).

1404424411431 is an equidigital number, since it uses as much as digits as its factorization.

1404424411431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 468141470480.

The product of its (nonzero) digits is 24576, while the sum is 33.

Adding to 1404424411431 its reverse (1341144244041), we get a palindrome (2745568655472).

The spelling of 1404424411431 in words is "one trillion, four hundred four billion, four hundred twenty-four million, four hundred eleven thousand, four hundred thirty-one".