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1404424411471 is a prime number
BaseRepresentation
bin10100011011111110001…
…101111101100101001111
311222021001202022012000101
4110123332031331211033
5141002230122131341
62553103401111531
7203315642346604
oct24337615754517
94867052265011
101404424411471
114a1681a700a4
121a822aa885a7
13a258a436223
144bd9007a6ab
15267eb7bb831
hex146fe37d94f

1404424411471 has 2 divisors, whose sum is σ = 1404424411472. Its totient is φ = 1404424411470.

The previous prime is 1404424411399. The next prime is 1404424411477. The reversal of 1404424411471 is 1741144244041.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1404424411471 is a prime.

It is a super-3 number, since 3×14044244114713 (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1404424411471.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1404424411477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 702212205735 + 702212205736.

It is an arithmetic number, because the mean of its divisors is an integer number (702212205736).

Almost surely, 21404424411471 is an apocalyptic number.

1404424411471 is a deficient number, since it is larger than the sum of its proper divisors (1).

1404424411471 is an equidigital number, since it uses as much as digits as its factorization.

1404424411471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 57344, while the sum is 37.

The spelling of 1404424411471 in words is "one trillion, four hundred four billion, four hundred twenty-four million, four hundred eleven thousand, four hundred seventy-one".