Base | Representation |
---|---|
bin | 10100011011111110100… |
… | …101011001000100000111 |
3 | 11222021002011212020002102 |
4 | 110123332211121010013 |
5 | 141002233210201401 |
6 | 2553104140502315 |
7 | 203316045510140 |
oct | 24337645310407 |
9 | 4867064766072 |
10 | 1404430553351 |
11 | 4a1685485631 |
12 | 1a8230b4a99b |
13 | a258b7a6987 |
14 | 4bd90bd8ac7 |
15 | 267ec0d156b |
hex | 146fe959107 |
1404430553351 has 8 divisors (see below), whose sum is σ = 1648443584160. Its totient is φ = 1171262546208.
The previous prime is 1404430553347. The next prime is 1404430553363. The reversal of 1404430553351 is 1533550344041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1404430553351 - 22 = 1404430553347 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1404430553311) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2711255636 + ... + 2711256153.
It is an arithmetic number, because the mean of its divisors is an integer number (206055448020).
Almost surely, 21404430553351 is an apocalyptic number.
1404430553351 is a deficient number, since it is larger than the sum of its proper divisors (244013030809).
1404430553351 is an equidigital number, since it uses as much as digits as its factorization.
1404430553351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5422511833.
The product of its (nonzero) digits is 216000, while the sum is 38.
Adding to 1404430553351 its reverse (1533550344041), we get a palindrome (2937980897392).
The spelling of 1404430553351 in words is "one trillion, four hundred four billion, four hundred thirty million, five hundred fifty-three thousand, three hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •