Base | Representation |
---|---|
bin | 1100110001011111001000… |
… | …1000101011111101110011 |
3 | 1211201121211010212020201022 |
4 | 3030113302020223331303 |
5 | 3320100221434013011 |
6 | 45511511145530055 |
7 | 2646445051115036 |
oct | 314276210537563 |
9 | 54647733766638 |
10 | 14044310454131 |
11 | 4525182131711 |
12 | 16a9a6b1a392b |
13 | 7ab4b0046189 |
14 | 367a692c501d |
15 | 1954d10318db |
hex | cc5f222bf73 |
14044310454131 has 2 divisors, whose sum is σ = 14044310454132. Its totient is φ = 14044310454130.
The previous prime is 14044310454091. The next prime is 14044310454191. The reversal of 14044310454131 is 13145401344041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14044310454131 - 218 = 14044310191987 is a prime.
It is a super-2 number, since 2×140443104541312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14044310454091 and 14044310454100.
It is not a weakly prime, because it can be changed into another prime (14044310454191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7022155227065 + 7022155227066.
It is an arithmetic number, because the mean of its divisors is an integer number (7022155227066).
Almost surely, 214044310454131 is an apocalyptic number.
14044310454131 is a deficient number, since it is larger than the sum of its proper divisors (1).
14044310454131 is an equidigital number, since it uses as much as digits as its factorization.
14044310454131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46080, while the sum is 35.
Adding to 14044310454131 its reverse (13145401344041), we get a palindrome (27189711798172).
The spelling of 14044310454131 in words is "fourteen trillion, forty-four billion, three hundred ten million, four hundred fifty-four thousand, one hundred thirty-one".
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