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14044325101 = 54725675183
BaseRepresentation
bin11010001010001101…
…10110010011101101
31100020202212122011221
431011012312103231
5212230321400401
610241334343341
71005013536142
oct150506662355
940222778157
1014044325101
115a57723354
12287b4bab51
13142a85b251
149733343c9
15572e8b7a1
hex3451b64ed

14044325101 has 4 divisors (see below), whose sum is σ = 14070000832. Its totient is φ = 14018649372.

The previous prime is 14044325089. The next prime is 14044325137. The reversal of 14044325101 is 10152344041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14044325101 - 221 = 14042227949 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14044325161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12837045 + ... + 12838138.

It is an arithmetic number, because the mean of its divisors is an integer number (3517500208).

Almost surely, 214044325101 is an apocalyptic number.

It is an amenable number.

14044325101 is a deficient number, since it is larger than the sum of its proper divisors (25675731).

14044325101 is an equidigital number, since it uses as much as digits as its factorization.

14044325101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25675730.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 14044325101 its reverse (10152344041), we get a palindrome (24196669142).

The spelling of 14044325101 in words is "fourteen billion, forty-four million, three hundred twenty-five thousand, one hundred one".

Divisors: 1 547 25675183 14044325101