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14044340221 = 52667266663
BaseRepresentation
bin11010001010001101…
…11001111111111101
31100020202220101220221
431011012321333331
5212230322341341
610241334541341
71005013631212
oct150506717775
940222811827
1014044340221
115a5773374a
12287b507851
13142a8650b2
14973339b09
15572e90ed1
hex3451b9ffd

14044340221 has 4 divisors (see below), whose sum is σ = 14044659552. Its totient is φ = 14044020892.

The previous prime is 14044340213. The next prime is 14044340263. The reversal of 14044340221 is 12204344041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14044340221 - 23 = 14044340213 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14044340281) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80665 + ... + 185998.

It is an arithmetic number, because the mean of its divisors is an integer number (3511164888).

Almost surely, 214044340221 is an apocalyptic number.

It is an amenable number.

14044340221 is a deficient number, since it is larger than the sum of its proper divisors (319331).

14044340221 is an equidigital number, since it uses as much as digits as its factorization.

14044340221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 319330.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 14044340221 its reverse (12204344041), we get a palindrome (26248684262).

The spelling of 14044340221 in words is "fourteen billion, forty-four million, three hundred forty thousand, two hundred twenty-one".

Divisors: 1 52667 266663 14044340221