140444340013111 has 4 divisors (see below), whose sum is σ = 140460927282712. Its totient is φ = 140427752743512.

The previous prime is 140444340013079. The next prime is 140444340013157. The reversal of 140444340013111 is 111310043444041.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140444340013111 - 2⁵ = 140444340013079 is a prime.

It is a super-2 number, since 2×140444340013111² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140444340013171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8293622100 + ... + 8293639033.

It is an arithmetic number, because the mean of its divisors is an integer number (35115231820678).

Almost surely, 2^{140444340013111} is an apocalyptic number.

140444340013111 is a deficient number, since it is larger than the sum of its proper divisors (16587269601).

140444340013111 is an equidigital number, since it uses as much as digits as its factorization.

140444340013111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16587269600.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 140444340013111 its reverse (111310043444041), we get a palindrome (251754383457152).

The spelling of 140444340013111 in words is "one hundred forty trillion, four hundred forty-four billion, three hundred forty million, thirteen thousand, one hundred eleven".