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14044450033 is a prime number
BaseRepresentation
bin11010001010001110…
…10100110011110001
31100020210002222120001
431011013110303301
5212230334400113
610241341150001
71005014566315
oct150507246361
940223088501
1014044450033
115a577a91a9
12287b55b301
13142a8a3083
14973367b45
15572eb37dd
hex3451d4cf1

14044450033 has 2 divisors, whose sum is σ = 14044450034. Its totient is φ = 14044450032.

The previous prime is 14044450027. The next prime is 14044450073. The reversal of 14044450033 is 33005444041.

14044450033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13793797809 + 250652224 = 117447^2 + 15832^2 .

It is a cyclic number.

It is not a de Polignac number, because 14044450033 - 217 = 14044318961 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14044449983 and 14044450010.

It is not a weakly prime, because it can be changed into another prime (14044450073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7022225016 + 7022225017.

It is an arithmetic number, because the mean of its divisors is an integer number (7022225017).

Almost surely, 214044450033 is an apocalyptic number.

It is an amenable number.

14044450033 is a deficient number, since it is larger than the sum of its proper divisors (1).

14044450033 is an equidigital number, since it uses as much as digits as its factorization.

14044450033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 28.

Adding to 14044450033 its reverse (33005444041), we get a palindrome (47049894074).

The spelling of 14044450033 in words is "fourteen billion, forty-four million, four hundred fifty thousand, thirty-three".