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140455051110193 is a prime number
BaseRepresentation
bin11111111011111000111101…
…011011011010011100110001
3200102022101001000012001210011
4133323320331123122130301
5121402203421041011233
61214420054255334521
741404354046640451
oct3773707533323461
9612271030161704
10140455051110193
114083171a772526
1213905168521441
13604ab15403b51
1426980bc987d61
151138858e2a0cd
hex7fbe3d6da731

140455051110193 has 2 divisors, whose sum is σ = 140455051110194. Its totient is φ = 140455051110192.

The previous prime is 140455051110091. The next prime is 140455051110203. The reversal of 140455051110193 is 391011150554041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113372727361569 + 27082323748624 = 10647663^2 + 5204068^2 .

It is a cyclic number.

It is not a de Polignac number, because 140455051110193 - 241 = 138256027854641 is a prime.

It is not a weakly prime, because it can be changed into another prime (140455051810193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70227525555096 + 70227525555097.

It is an arithmetic number, because the mean of its divisors is an integer number (70227525555097).

Almost surely, 2140455051110193 is an apocalyptic number.

It is an amenable number.

140455051110193 is a deficient number, since it is larger than the sum of its proper divisors (1).

140455051110193 is an equidigital number, since it uses as much as digits as its factorization.

140455051110193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54000, while the sum is 40.

The spelling of 140455051110193 in words is "one hundred forty trillion, four hundred fifty-five billion, fifty-one million, one hundred ten thousand, one hundred ninety-three".