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14047225921 is a prime number
BaseRepresentation
bin11010001010100011…
…11010100001000001
31100020222100000100201
431011101322201001
5212232042212141
610241520445201
71005050310301
oct150521724101
940228300321
1014047225921
115a59324823
122880479801
13142b335701
1497388b601
15573361031
hex34547a841

14047225921 has 2 divisors, whose sum is σ = 14047225922. Its totient is φ = 14047225920.

The previous prime is 14047225903. The next prime is 14047225937. The reversal of 14047225921 is 12952274041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13401303696 + 645922225 = 115764^2 + 25415^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14047225921 is a prime.

It is a super-2 number, since 2×140472259212 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14047225961) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7023612960 + 7023612961.

It is an arithmetic number, because the mean of its divisors is an integer number (7023612961).

Almost surely, 214047225921 is an apocalyptic number.

It is an amenable number.

14047225921 is a deficient number, since it is larger than the sum of its proper divisors (1).

14047225921 is an equidigital number, since it uses as much as digits as its factorization.

14047225921 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 37.

Adding to 14047225921 its reverse (12952274041), we get a palindrome (26999499962).

The spelling of 14047225921 in words is "fourteen billion, forty-seven million, two hundred twenty-five thousand, nine hundred twenty-one".