Base | Representation |
---|---|
bin | 11010001010101010… |
… | …11001000110110011 |
3 | 1100021001001100000111 |
4 | 31011111121012303 |
5 | 212232310401101 |
6 | 10241552202151 |
7 | 1005061125352 |
oct | 150525310663 |
9 | 40231040014 |
10 | 14048137651 |
11 | 5a59897819 |
12 | 2880839357 |
13 | 142b5946b2 |
14 | 973a47999 |
15 | 573491251 |
hex | 3455591b3 |
14048137651 has 2 divisors, whose sum is σ = 14048137652. Its totient is φ = 14048137650.
The previous prime is 14048137637. The next prime is 14048137657. The reversal of 14048137651 is 15673184041.
14048137651 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14048137651 - 215 = 14048104883 is a prime.
It is a super-2 number, since 2×140481376512 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14048137657) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7024068825 + 7024068826.
It is an arithmetic number, because the mean of its divisors is an integer number (7024068826).
Almost surely, 214048137651 is an apocalyptic number.
14048137651 is a deficient number, since it is larger than the sum of its proper divisors (1).
14048137651 is an equidigital number, since it uses as much as digits as its factorization.
14048137651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80640, while the sum is 40.
The spelling of 14048137651 in words is "fourteen billion, forty-eight million, one hundred thirty-seven thousand, six hundred fifty-one".
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