1405041403 has 2 divisors, whose sum is σ = 1405041404. Its totient is φ = 1405041402.

The previous prime is 1405041377. The next prime is 1405041413. The reversal of 1405041403 is 3041405041.

It is a strong prime.

It is an emirp because it is prime and its reverse (3041405041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1405041403 - 2⁵ = 1405041371 is a prime.

It is not a weakly prime, because it can be changed into another prime (1405041413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 702520701 + 702520702.

It is an arithmetic number, because the mean of its divisors is an integer number (702520702).

Almost surely, 2^1405041403 is an apocalyptic number.

1405041403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1405041403 is an equidigital number, since it uses as much as digits as its factorization.

1405041403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 22.

The square root of 1405041403 is about 37483.8819094288. The cubic root of 1405041403 is about 1120.0301339150.

Adding to 1405041403 its reverse (3041405041), we get a palindrome (4446446444).

The spelling of 1405041403 in words is "one billion, four hundred five million, forty-one thousand, four hundred three".