14050440433 has 2 divisors, whose sum is σ = 14050440434. Its totient is φ = 14050440432.

The previous prime is 14050440379. The next prime is 14050440457. The reversal of 14050440433 is 33404405041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8665375744 + 5385064689 = 93088^2 + 73383^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14050440433 is a prime.

It is a super-2 number, since 2×14050440433² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14050449433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7025220216 + 7025220217.

It is an arithmetic number, because the mean of its divisors is an integer number (7025220217).

Almost surely, 2^14050440433 is an apocalyptic number.

It is an amenable number.

14050440433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14050440433 is an equidigital number, since it uses as much as digits as its factorization.

14050440433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 28.

Adding to 14050440433 its reverse (33404405041), we get a palindrome (47454845474).

The spelling of 14050440433 in words is "fourteen billion, fifty million, four hundred forty thousand, four hundred thirty-three".