Base | Representation |
---|---|
bin | 11010001011001111… |
… | …11100010011110001 |
3 | 1100021101012101111112 |
4 | 31011213330103301 |
5 | 212240032003213 |
6 | 10242244323105 |
7 | 1005150350513 |
oct | 150547742361 |
9 | 40241171445 |
10 | 14053000433 |
11 | 5a6160924a |
12 | 28823a3495 |
13 | 142c5a7b94 |
14 | 974551bb3 |
15 | 573b01ea8 |
hex | 3459fc4f1 |
14053000433 has 2 divisors, whose sum is σ = 14053000434. Its totient is φ = 14053000432.
The previous prime is 14053000361. The next prime is 14053000447. The reversal of 14053000433 is 33400035041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13615855969 + 437144464 = 116687^2 + 20908^2 .
It is a cyclic number.
It is not a de Polignac number, because 14053000433 - 216 = 14052934897 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14053000399 and 14053000408.
It is not a weakly prime, because it can be changed into another prime (14053000453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7026500216 + 7026500217.
It is an arithmetic number, because the mean of its divisors is an integer number (7026500217).
Almost surely, 214053000433 is an apocalyptic number.
It is an amenable number.
14053000433 is a deficient number, since it is larger than the sum of its proper divisors (1).
14053000433 is an equidigital number, since it uses as much as digits as its factorization.
14053000433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2160, while the sum is 23.
Adding to 14053000433 its reverse (33400035041), we get a palindrome (47453035474).
The spelling of 14053000433 in words is "fourteen billion, fifty-three million, four hundred thirty-three", and thus it is an aban number.
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