Base | Representation |
---|---|
bin | 1100110001111111111001… |
… | …0001011111101111010011 |
3 | 1211202110111222111220112220 |
4 | 3030133332101133233103 |
5 | 3320221224112241111 |
6 | 45515523514352123 |
7 | 2650206006202365 |
oct | 314377621375723 |
9 | 54673458456486 |
10 | 14053104024531 |
11 | 4528984949270 |
12 | 16ab70412b643 |
13 | 7ac281aca780 |
14 | 368261122d35 |
15 | 195848033e06 |
hex | cc7fe45fbd3 |
14053104024531 has 32 divisors (see below), whose sum is σ = 22105359682560. Its totient is φ = 7828981440000.
The previous prime is 14053104024527. The next prime is 14053104024559. The reversal of 14053104024531 is 13542040135041.
It is not a de Polignac number, because 14053104024531 - 22 = 14053104024527 is a prime.
It is a super-2 number, since 2×140531040245312 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a junction number, because it is equal to n+sod(n) for n = 14053104024492 and 14053104024501.
It is not an unprimeable number, because it can be changed into a prime (14053104024031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 68428470 + ... + 68633531.
It is an arithmetic number, because the mean of its divisors is an integer number (690792490080).
Almost surely, 214053104024531 is an apocalyptic number.
14053104024531 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
14053104024531 is a deficient number, since it is larger than the sum of its proper divisors (8052255658029).
14053104024531 is a wasteful number, since it uses less digits than its factorization.
14053104024531 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 137062267.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 14053104024531 its reverse (13542040135041), we get a palindrome (27595144159572).
The spelling of 14053104024531 in words is "fourteen trillion, fifty-three billion, one hundred four million, twenty-four thousand, five hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •