14053125114132 has 48 divisors (see below), whose sum is σ = 35315530111680. Its totient is φ = 4323726367488.

The previous prime is 14053125114059. The next prime is 14053125114139. The reversal of 14053125114132 is 23141152135041.

It is a super-2 number, since 2×14053125114132² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14053125114093 and 14053125114102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14053125114139) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1078657 + ... + 5410152.

It is an arithmetic number, because the mean of its divisors is an integer number (735740210660).

Almost surely, 2^{14053125114132} is an apocalyptic number.

14053125114132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

14053125114132 is an abundant number, since it is smaller than the sum of its proper divisors (21262404997548).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14053125114132 is a wasteful number, since it uses less digits than its factorization.

14053125114132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6502712 (or 6502710 counting only the distinct ones).

The product of its (nonzero) digits is 14400, while the sum is 33.

Adding to 14053125114132 its reverse (23141152135041), we get a palindrome (37194277249173).

The spelling of 14053125114132 in words is "fourteen trillion, fifty-three billion, one hundred twenty-five million, one hundred fourteen thousand, one hundred thirty-two".