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14053242543233 is a prime number
BaseRepresentation
bin1100110010000000011010…
…0001111001110010000001
31211202110212122011101111012
43030200012201321302001
53320222020042340413
645515545343330305
72650212310453115
oct314400641716201
954673778141435
1014053242543233
114528a46059433
1216ab7425b0995
137ac2a47097ba
1436827569d745
151958552967a8
hexcc806879c81

14053242543233 has 2 divisors, whose sum is σ = 14053242543234. Its totient is φ = 14053242543232.

The previous prime is 14053242543229. The next prime is 14053242543271. The reversal of 14053242543233 is 33234524235041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12587537643664 + 1465704899569 = 3547892^2 + 1210663^2 .

It is a cyclic number.

It is not a de Polignac number, because 14053242543233 - 22 = 14053242543229 is a prime.

It is not a weakly prime, because it can be changed into another prime (14053242543283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7026621271616 + 7026621271617.

It is an arithmetic number, because the mean of its divisors is an integer number (7026621271617).

Almost surely, 214053242543233 is an apocalyptic number.

It is an amenable number.

14053242543233 is a deficient number, since it is larger than the sum of its proper divisors (1).

14053242543233 is an equidigital number, since it uses as much as digits as its factorization.

14053242543233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1036800, while the sum is 41.

Adding to 14053242543233 its reverse (33234524235041), we get a palindrome (47287766778274).

The spelling of 14053242543233 in words is "fourteen trillion, fifty-three billion, two hundred forty-two million, five hundred forty-three thousand, two hundred thirty-three".