Base | Representation |
---|---|
bin | 11111111101000010111110… |
… | …110011100011110101111010 |
3 | 200102120222012002211111210102 |
4 | 133331002332303203311322 |
5 | 121410004204431043224 |
6 | 1214520401115515402 |
7 | 41413166455545323 |
oct | 3775027663436572 |
9 | 612528162744712 |
10 | 140534531112314 |
11 | 408623a60a3499 |
12 | 1391864a158b62 |
13 | 60554708a13c1 |
14 | 269bc9c64344a |
15 | 113a95b9304ae |
hex | 7fd0bece3d7a |
140534531112314 has 4 divisors (see below), whose sum is σ = 210801796668474. Its totient is φ = 70267265556156.
The previous prime is 140534531112257. The next prime is 140534531112319. The reversal of 140534531112314 is 413211135435041.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 139411742925625 + 1122788186689 = 11807275^2 + 1059617^2 .
It is not an unprimeable number, because it can be changed into a prime (140534531112319) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35133632778077 + ... + 35133632778080.
Almost surely, 2140534531112314 is an apocalyptic number.
140534531112314 is a deficient number, since it is larger than the sum of its proper divisors (70267265556160).
140534531112314 is an equidigital number, since it uses as much as digits as its factorization.
140534531112314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70267265556159.
The product of its (nonzero) digits is 86400, while the sum is 38.
Adding to 140534531112314 its reverse (413211135435041), we get a palindrome (553745666547355).
The spelling of 140534531112314 in words is "one hundred forty trillion, five hundred thirty-four billion, five hundred thirty-one million, one hundred twelve thousand, three hundred fourteen".
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