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14055055555003 is a prime number
BaseRepresentation
bin1100110010000111001010…
…0101111111100110111011
31211202122112222122221002021
43030201302211333212323
53320234223210230003
645520445310415311
72650305244012531
oct314416245774673
954678488587067
1014055055555003
11452979649aa71
1216abb69801537
137ac503204228
143683a83a2151
1519590e5202bd
hexcc87297f9bb

14055055555003 has 2 divisors, whose sum is σ = 14055055555004. Its totient is φ = 14055055555002.

The previous prime is 14055055554997. The next prime is 14055055555033. The reversal of 14055055555003 is 30055555055041.

It is a weak prime.

It is an emirp because it is prime and its reverse (30055555055041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14055055555003 - 25 = 14055055554971 is a prime.

It is not a weakly prime, because it can be changed into another prime (14055055555033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7027527777501 + 7027527777502.

It is an arithmetic number, because the mean of its divisors is an integer number (7027527777502).

Almost surely, 214055055555003 is an apocalyptic number.

14055055555003 is a deficient number, since it is larger than the sum of its proper divisors (1).

14055055555003 is an equidigital number, since it uses as much as digits as its factorization.

14055055555003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 937500, while the sum is 43.

The spelling of 14055055555003 in words is "fourteen trillion, fifty-five billion, fifty-five million, five hundred fifty-five thousand, three".