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14055111011 is a prime number
BaseRepresentation
bin11010001011011111…
…11111100101100011
31100021112011121200002
431011233333211203
5212241102023021
610242401450215
71005204321014
oct150557774543
940245147602
1014055111011
115a6281aa27
12288304096b
13142cb66746
1497494100b
15573dbc50b
hex345bff963

14055111011 has 2 divisors, whose sum is σ = 14055111012. Its totient is φ = 14055111010.

The previous prime is 14055110989. The next prime is 14055111017. The reversal of 14055111011 is 11011155041.

It is a strong prime.

It is an emirp because it is prime and its reverse (11011155041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14055111011 - 218 = 14054848867 is a prime.

It is a super-2 number, since 2×140551110112 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14055111017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7027555505 + 7027555506.

It is an arithmetic number, because the mean of its divisors is an integer number (7027555506).

Almost surely, 214055111011 is an apocalyptic number.

14055111011 is a deficient number, since it is larger than the sum of its proper divisors (1).

14055111011 is an equidigital number, since it uses as much as digits as its factorization.

14055111011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 100, while the sum is 20.

Adding to 14055111011 its reverse (11011155041), we get a palindrome (25066266052).

The spelling of 14055111011 in words is "fourteen billion, fifty-five million, one hundred eleven thousand, eleven".