Base | Representation |
---|---|
bin | 11010001011100001… |
… | …10001000010000001 |
3 | 1100021112112220111001 |
4 | 31011300301002001 |
5 | 212241130013122 |
6 | 10242410052001 |
7 | 1005206123326 |
oct | 150560610201 |
9 | 40245486431 |
10 | 14055313537 |
11 | 5a62949101 |
12 | 288311a001 |
13 | 142cc07995 |
14 | 974994b4d |
15 | 573e0c527 |
hex | 345c31081 |
14055313537 has 2 divisors, whose sum is σ = 14055313538. Its totient is φ = 14055313536.
The previous prime is 14055313427. The next prime is 14055313549. The reversal of 14055313537 is 73531355041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13997492721 + 57820816 = 118311^2 + 7604^2 .
It is a cyclic number.
It is not a de Polignac number, because 14055313537 - 219 = 14054789249 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14055313496 and 14055313505.
It is not a weakly prime, because it can be changed into another prime (14055313037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7027656768 + 7027656769.
It is an arithmetic number, because the mean of its divisors is an integer number (7027656769).
Almost surely, 214055313537 is an apocalyptic number.
It is an amenable number.
14055313537 is a deficient number, since it is larger than the sum of its proper divisors (1).
14055313537 is an equidigital number, since it uses as much as digits as its factorization.
14055313537 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 94500, while the sum is 37.
Adding to 14055313537 its reverse (73531355041), we get a palindrome (87586668578).
The spelling of 14055313537 in words is "fourteen billion, fifty-five million, three hundred thirteen thousand, five hundred thirty-seven".
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