Base | Representation |
---|---|
bin | 11010001100000000… |
… | …11001101010000111 |
3 | 1100021211021010122210 |
4 | 31012000121222013 |
5 | 212243202141403 |
6 | 10243033554503 |
7 | 1005256013442 |
oct | 150600315207 |
9 | 40254233583 |
10 | 14059412103 |
11 | 5a65198450 |
12 | 2884575a33 |
13 | 1430a11379 |
14 | 975340659 |
15 | 57446bb03 |
hex | 346019a87 |
14059412103 has 8 divisors (see below), whose sum is σ = 20450054016. Its totient is φ = 8520855800.
The previous prime is 14059412047. The next prime is 14059412123. The reversal of 14059412103 is 30121495041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14059412103 - 217 = 14059281031 is a prime.
It is a super-3 number, since 3×140594121033 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14059412123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 213021363 + ... + 213021428.
It is an arithmetic number, because the mean of its divisors is an integer number (2556256752).
Almost surely, 214059412103 is an apocalyptic number.
14059412103 is a deficient number, since it is larger than the sum of its proper divisors (6390641913).
14059412103 is a wasteful number, since it uses less digits than its factorization.
14059412103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 426042805.
The product of its (nonzero) digits is 4320, while the sum is 30.
The spelling of 14059412103 in words is "fourteen billion, fifty-nine million, four hundred twelve thousand, one hundred three".
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