1406142529993 has 2 divisors, whose sum is σ = 1406142529994. Its totient is φ = 1406142529992.

The previous prime is 1406142529931. The next prime is 1406142530027. The reversal of 1406142529993 is 3999252416041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1125228749824 + 280913780169 = 1060768^2 + 530013^2 .

It is a cyclic number.

It is not a de Polignac number, because 1406142529993 - 2⁹ = 1406142529481 is a prime.

It is a super-3 number, since 3×1406142529993³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1406142529793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 703071264996 + 703071264997.

It is an arithmetic number, because the mean of its divisors is an integer number (703071264997).

Almost surely, 2^{1406142529993} is an apocalyptic number.

It is an amenable number.

1406142529993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1406142529993 is an equidigital number, since it uses as much as digits as its factorization.

1406142529993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4199040, while the sum is 55.

The spelling of 1406142529993 in words is "one trillion, four hundred six billion, one hundred forty-two million, five hundred twenty-nine thousand, nine hundred ninety-three".