Base | Representation |
---|---|
bin | 10100011101101110101… |
… | …011110111110110110110 |
3 | 11222102221020211002012111 |
4 | 110131232223313312312 |
5 | 141020111143104114 |
6 | 2554014523441234 |
7 | 203413463552110 |
oct | 24355653676666 |
9 | 4872836732174 |
10 | 1406311300534 |
11 | 4a2460080848 |
12 | 1a867698621a |
13 | a27cb32922a |
14 | 4c0cc8d03b0 |
15 | 268ac289bc4 |
hex | 1476eaf7db6 |
1406311300534 has 16 divisors (see below), whose sum is σ = 2416026336768. Its totient is φ = 601403101992.
The previous prime is 1406311300523. The next prime is 1406311300549. The reversal of 1406311300534 is 4350031136041.
It is a super-2 number, since 2×14063113005342 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1406311300496 and 1406311300505.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 108471712 + ... + 108484675.
It is an arithmetic number, because the mean of its divisors is an integer number (151001646048).
Almost surely, 21406311300534 is an apocalyptic number.
1406311300534 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
1406311300534 is a deficient number, since it is larger than the sum of its proper divisors (1009715036234).
1406311300534 is a wasteful number, since it uses less digits than its factorization.
1406311300534 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 216956859.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 1406311300534 its reverse (4350031136041), we get a palindrome (5756342436575).
The spelling of 1406311300534 in words is "one trillion, four hundred six billion, three hundred eleven million, three hundred thousand, five hundred thirty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •