Base | Representation |
---|---|
bin | 11010001101010100… |
… | …11011111000010011 |
3 | 1100022120222222002101 |
4 | 31012222123320103 |
5 | 212304012300001 |
6 | 10244110101231 |
7 | 1005451456312 |
oct | 150652337023 |
9 | 40276888071 |
10 | 14070431251 |
11 | 5a70434288 |
12 | 28881aa817 |
13 | 143309ba86 |
14 | 9769ac279 |
15 | 5753e6a01 |
hex | 346a9be13 |
14070431251 has 2 divisors, whose sum is σ = 14070431252. Its totient is φ = 14070431250.
The previous prime is 14070431239. The next prime is 14070431269. The reversal of 14070431251 is 15213407041.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14070431251 is a prime.
It is not a weakly prime, because it can be changed into another prime (14070431281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7035215625 + 7035215626.
It is an arithmetic number, because the mean of its divisors is an integer number (7035215626).
Almost surely, 214070431251 is an apocalyptic number.
14070431251 is a deficient number, since it is larger than the sum of its proper divisors (1).
14070431251 is an equidigital number, since it uses as much as digits as its factorization.
14070431251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3360, while the sum is 28.
Adding to 14070431251 its reverse (15213407041), we get a palindrome (29283838292).
The spelling of 14070431251 in words is "fourteen billion, seventy million, four hundred thirty-one thousand, two hundred fifty-one".
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