Base | Representation |
---|---|
bin | 11010001101100010… |
… | …11100101001111001 |
3 | 1100022201110100121012 |
4 | 31012301130221321 |
5 | 212310000110213 |
6 | 10244213323305 |
7 | 1005503213405 |
oct | 150661345171 |
9 | 40281410535 |
10 | 14072269433 |
11 | 5a7147a342 |
12 | 2888936535 |
13 | 1433593661 |
14 | 976d2a105 |
15 | 57565b4a8 |
hex | 346c5ca79 |
14072269433 has 2 divisors, whose sum is σ = 14072269434. Its totient is φ = 14072269432.
The previous prime is 14072269429. The next prime is 14072269439. The reversal of 14072269433 is 33496227041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13176284944 + 895984489 = 114788^2 + 29933^2 .
It is a cyclic number.
It is not a de Polignac number, because 14072269433 - 22 = 14072269429 is a prime.
It is a super-2 number, since 2×140722694332 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14072269439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7036134716 + 7036134717.
It is an arithmetic number, because the mean of its divisors is an integer number (7036134717).
Almost surely, 214072269433 is an apocalyptic number.
It is an amenable number.
14072269433 is a deficient number, since it is larger than the sum of its proper divisors (1).
14072269433 is an equidigital number, since it uses as much as digits as its factorization.
14072269433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 217728, while the sum is 41.
The spelling of 14072269433 in words is "fourteen billion, seventy-two million, two hundred sixty-nine thousand, four hundred thirty-three".
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