Base | Representation |
---|---|
bin | 11111111111110100100110… |
… | …000101111010010001101011 |
3 | 200110021012110010000200110101 |
4 | 133333310212011322101223 |
5 | 121421120244042141232 |
6 | 1215144141155330231 |
7 | 41433030461114116 |
oct | 3777644605722153 |
9 | 613235403020411 |
10 | 140725242537067 |
11 | 40926270792621 |
12 | 139495b2bb0977 |
13 | 606a4447126b6 |
14 | 26a71d0c7157d |
15 | 11408be6c41e7 |
hex | 7ffd2617a46b |
140725242537067 has 2 divisors, whose sum is σ = 140725242537068. Its totient is φ = 140725242537066.
The previous prime is 140725242537037. The next prime is 140725242537071. The reversal of 140725242537067 is 760735242527041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140725242537067 - 223 = 140725234148459 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 140725242536999 and 140725242537017.
It is not a weakly prime, because it can be changed into another prime (140725242537037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70362621268533 + 70362621268534.
It is an arithmetic number, because the mean of its divisors is an integer number (70362621268534).
Almost surely, 2140725242537067 is an apocalyptic number.
140725242537067 is a deficient number, since it is larger than the sum of its proper divisors (1).
140725242537067 is an equidigital number, since it uses as much as digits as its factorization.
140725242537067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19756800, while the sum is 55.
The spelling of 140725242537067 in words is "one hundred forty trillion, seven hundred twenty-five billion, two hundred forty-two million, five hundred thirty-seven thousand, sixty-seven".
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