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14100131325041 is a prime number
BaseRepresentation
bin1100110100101111000101…
…0100011010010001110001
31211220221220101200022002122
43031023301110122101301
53322004032104400131
645553302204524025
72653462253515646
oct315136124322161
954827811608078
1014100131325041
1145469175a8183
1216b8849550615
137b3837a242c8
1436a642b15dcd
15196b9b928d7b
hexcd2f151a471

14100131325041 has 2 divisors, whose sum is σ = 14100131325042. Its totient is φ = 14100131325040.

The previous prime is 14100131325001. The next prime is 14100131325047. The reversal of 14100131325041 is 14052313100141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12108868848400 + 1991262476641 = 3479780^2 + 1411121^2 .

It is a cyclic number.

It is not a de Polignac number, because 14100131325041 - 210 = 14100131324017 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 14100131325041.

It is not a weakly prime, because it can be changed into another prime (14100131325047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7050065662520 + 7050065662521.

It is an arithmetic number, because the mean of its divisors is an integer number (7050065662521).

Almost surely, 214100131325041 is an apocalyptic number.

It is an amenable number.

14100131325041 is a deficient number, since it is larger than the sum of its proper divisors (1).

14100131325041 is an equidigital number, since it uses as much as digits as its factorization.

14100131325041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 14100131325041 its reverse (14052313100141), we get a palindrome (28152444425182).

The spelling of 14100131325041 in words is "fourteen trillion, one hundred billion, one hundred thirty-one million, three hundred twenty-five thousand, forty-one".