14100314321211 has 4 divisors (see below), whose sum is σ = 18800419094952. Its totient is φ = 9400209547472.

The previous prime is 14100314321209. The next prime is 14100314321273. The reversal of 14100314321211 is 11212341300141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14100314321211 - 2¹ = 14100314321209 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14100314321711) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2350052386866 + ... + 2350052386871.

It is an arithmetic number, because the mean of its divisors is an integer number (4700104773738).

Almost surely, 2^{14100314321211} is an apocalyptic number.

14100314321211 is a deficient number, since it is larger than the sum of its proper divisors (4700104773741).

14100314321211 is an equidigital number, since it uses as much as digits as its factorization.

14100314321211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4700104773740.

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 14100314321211 its reverse (11212341300141), we get a palindrome (25312655621352).

The spelling of 14100314321211 in words is "fourteen trillion, one hundred billion, three hundred fourteen million, three hundred twenty-one thousand, two hundred eleven".