14100314321711 has 2 divisors, whose sum is σ = 14100314321712. Its totient is φ = 14100314321710.

The previous prime is 14100314321701. The next prime is 14100314321713. The reversal of 14100314321711 is 11712341300141.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14100314321711 - 2¹⁴ = 14100314305327 is a prime.

Together with 14100314321713, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14100314321713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7050157160855 + 7050157160856.

It is an arithmetic number, because the mean of its divisors is an integer number (7050157160856).

Almost surely, 2^{14100314321711} is an apocalyptic number.

14100314321711 is a deficient number, since it is larger than the sum of its proper divisors (1).

14100314321711 is an equidigital number, since it uses as much as digits as its factorization.

14100314321711 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 29.

Adding to 14100314321711 its reverse (11712341300141), we get a palindrome (25812655621852).

The spelling of 14100314321711 in words is "fourteen trillion, one hundred billion, three hundred fourteen million, three hundred twenty-one thousand, seven hundred eleven".