141003230131 has 2 divisors, whose sum is σ = 141003230132. Its totient is φ = 141003230130.

The previous prime is 141003230119. The next prime is 141003230177. The reversal of 141003230131 is 131032300141.

It is a weak prime.

It is an emirp because it is prime and its reverse (131032300141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141003230131 - 2¹¹ = 141003228083 is a prime.

It is a super-2 number, since 2×141003230131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141003230099 and 141003230108.

It is not a weakly prime, because it can be changed into another prime (141003230191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70501615065 + 70501615066.

It is an arithmetic number, because the mean of its divisors is an integer number (70501615066).

Almost surely, 2^141003230131 is an apocalyptic number.

141003230131 is a deficient number, since it is larger than the sum of its proper divisors (1).

141003230131 is an equidigital number, since it uses as much as digits as its factorization.

141003230131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 141003230131 its reverse (131032300141), we get a palindrome (272035530272).

The spelling of 141003230131 in words is "one hundred forty-one billion, three million, two hundred thirty thousand, one hundred thirty-one".