1410040361131 has 4 divisors (see below), whose sum is σ = 1410075792664. Its totient is φ = 1410004929600.

The previous prime is 1410040361117. The next prime is 1410040361137. The reversal of 1410040361131 is 1311630400141.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1410040361131 - 2²¹ = 1410038263979 is a prime.

It is a super-2 number, since 2×1410040361131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1410040361096 and 1410040361105.

It is not an unprimeable number, because it can be changed into a prime (1410040361137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17656005 + ... + 17735686.

It is an arithmetic number, because the mean of its divisors is an integer number (352518948166).

Almost surely, 2^{1410040361131} is an apocalyptic number.

1410040361131 is a deficient number, since it is larger than the sum of its proper divisors (35431533).

1410040361131 is an equidigital number, since it uses as much as digits as its factorization.

1410040361131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35431532.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 1410040361131 its reverse (1311630400141), we get a palindrome (2721670761272).

The spelling of 1410040361131 in words is "one trillion, four hundred ten billion, forty million, three hundred sixty-one thousand, one hundred thirty-one".