14101011244431 has 24 divisors (see below), whose sum is σ = 21440373318000. Its totient is φ = 8905802452992.

The previous prime is 14101011244429. The next prime is 14101011244483. The reversal of 14101011244431 is 13444211010141.

14101011244431 is a `hidden beast` number, since 1 + 4 + 1 + 0 + 101 + 124 + 4 + 431 = 666.

It is not a de Polignac number, because 14101011244431 - 2¹ = 14101011244429 is a prime.

It is a super-2 number, since 2×14101011244431² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14101011244395 and 14101011244404.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14101011240431) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 16794325 + ... + 17613953.

It is an arithmetic number, because the mean of its divisors is an integer number (893348888250).

Almost surely, 2^{14101011244431} is an apocalyptic number.

14101011244431 is a deficient number, since it is larger than the sum of its proper divisors (7339362073569).

14101011244431 is a wasteful number, since it uses less digits than its factorization.

14101011244431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 920263 (or 920260 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 27.

Adding to 14101011244431 its reverse (13444211010141), we get a palindrome (27545222254572).

The spelling of 14101011244431 in words is "fourteen trillion, one hundred one billion, eleven million, two hundred forty-four thousand, four hundred thirty-one".