141010211 has 2 divisors, whose sum is σ = 141010212. Its totient is φ = 141010210.

The previous prime is 141010187. The next prime is 141010237. The reversal of 141010211 is 112010141.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141010211 is a prime.

It is a super-3 number, since 3×141010211³ (a number of 25 digits) contains 333 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 141010192 and 141010201.

It is not a weakly prime, because it can be changed into another prime (141010511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70505105 + 70505106.

It is an arithmetic number, because the mean of its divisors is an integer number (70505106).

Almost surely, 2^141010211 is an apocalyptic number.

141010211 is a deficient number, since it is larger than the sum of its proper divisors (1).

141010211 is an equidigital number, since it uses as much as digits as its factorization.

141010211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 11.

The square root of 141010211 is about 11874.7720399172. The cubic root of 141010211 is about 520.4953502199.

Adding to 141010211 its reverse (112010141), we get a palindrome (253020352).

The spelling of 141010211 in words is "one hundred forty-one million, ten thousand, two hundred eleven".