Base | Representation |
---|---|
bin | 1100110100110010011110… |
… | …1111101101100001010011 |
3 | 1211221001021000212220222211 |
4 | 3031030213233231201103 |
5 | 3322012414334421121 |
6 | 45553532544212551 |
7 | 2653524012124651 |
oct | 315144757554123 |
9 | 54831230786884 |
10 | 14101044451411 |
11 | 4547245a85575 |
12 | 16b8a6330a157 |
13 | 7b3951c65578 |
14 | 36a6cc0cbdd1 |
15 | 196c01b99ce1 |
hex | cd327bed853 |
14101044451411 has 2 divisors, whose sum is σ = 14101044451412. Its totient is φ = 14101044451410.
The previous prime is 14101044451397. The next prime is 14101044451421. The reversal of 14101044451411 is 11415444010141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14101044451411 - 25 = 14101044451379 is a prime.
It is not a weakly prime, because it can be changed into another prime (14101044451421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7050522225705 + 7050522225706.
It is an arithmetic number, because the mean of its divisors is an integer number (7050522225706).
Almost surely, 214101044451411 is an apocalyptic number.
14101044451411 is a deficient number, since it is larger than the sum of its proper divisors (1).
14101044451411 is an equidigital number, since it uses as much as digits as its factorization.
14101044451411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5120, while the sum is 31.
Adding to 14101044451411 its reverse (11415444010141), we get a palindrome (25516488461552).
The spelling of 14101044451411 in words is "fourteen trillion, one hundred one billion, forty-four million, four hundred fifty-one thousand, four hundred eleven".
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