Base | Representation |
---|---|
bin | 11010010000111110… |
… | …11100011000000011 |
3 | 1100101201201022100222 |
4 | 31020133130120003 |
5 | 212334340313011 |
6 | 10251123333255 |
7 | 1006303256522 |
oct | 151037343003 |
9 | 40351638328 |
10 | 14101104131 |
11 | 5a86784274 |
12 | 289652122b |
13 | 143954b0ca |
14 | 97aab44b9 |
15 | 577e54ddb |
hex | 3487dc603 |
14101104131 has 4 divisors (see below), whose sum is σ = 14279599200. Its totient is φ = 13922609064.
The previous prime is 14101104119. The next prime is 14101104133. The reversal of 14101104131 is 13140110141.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13140110141 = 97 ⋅135465053.
It is a cyclic number.
It is not a de Polignac number, because 14101104131 - 26 = 14101104067 is a prime.
It is a super-2 number, since 2×141011041312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14101104133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89247416 + ... + 89247573.
It is an arithmetic number, because the mean of its divisors is an integer number (3569899800).
Almost surely, 214101104131 is an apocalyptic number.
14101104131 is a deficient number, since it is larger than the sum of its proper divisors (178495069).
14101104131 is an equidigital number, since it uses as much as digits as its factorization.
14101104131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 178495068.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 14101104131 its reverse (13140110141), we get a palindrome (27241214272).
The spelling of 14101104131 in words is "fourteen billion, one hundred one million, one hundred four thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •