13140110141 has 4 divisors (see below), whose sum is σ = 13275575292. Its totient is φ = 13004644992.

The previous prime is 13140110111. The next prime is 13140110161. The reversal of 13140110141 is 14101104131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 14101104131 = 79 ⋅178494989.

It can be written as a sum of positive squares in 2 ways, for example, as 5837724025 + 7302386116 = 76405^2 + 85454^2 .

It is a cyclic number.

It is not a de Polignac number, because 13140110141 - 2⁶ = 13140110077 is a prime.

It is a super-2 number, since 2×13140110141² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13140110111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67732430 + ... + 67732623.

It is an arithmetic number, because the mean of its divisors is an integer number (3318893823).

Almost surely, 2^13140110141 is an apocalyptic number.

It is an amenable number.

13140110141 is a deficient number, since it is larger than the sum of its proper divisors (135465151).

13140110141 is an equidigital number, since it uses as much as digits as its factorization.

13140110141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 135465150.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 13140110141 its reverse (14101104131), we get a palindrome (27241214272).

The spelling of 13140110141 in words is "thirteen billion, one hundred forty million, one hundred ten thousand, one hundred forty-one".