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14102011403 = 103913572677
BaseRepresentation
bin11010010001000101…
…11001111000001011
31100101210102101220122
431020202321320023
5212340103331103
610251155013455
71006314055604
oct151042717013
940353371818
1014102011403
115a87243987
12289689a28b
1314397a805c
1497ac6cdab
15578083b38
hex3488b9e0b

14102011403 has 4 divisors (see below), whose sum is σ = 14115585120. Its totient is φ = 14088437688.

The previous prime is 14102011397. The next prime is 14102011433. The reversal of 14102011403 is 30411020141.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14102011403 - 24 = 14102011387 is a prime.

It is a super-2 number, since 2×141020114032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14102011433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6785300 + ... + 6787377.

It is an arithmetic number, because the mean of its divisors is an integer number (3528896280).

Almost surely, 214102011403 is an apocalyptic number.

14102011403 is a deficient number, since it is larger than the sum of its proper divisors (13573717).

14102011403 is a wasteful number, since it uses less digits than its factorization.

14102011403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13573716.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 14102011403 its reverse (30411020141), we get a palindrome (44513031544).

The spelling of 14102011403 in words is "fourteen billion, one hundred two million, eleven thousand, four hundred three".

Divisors: 1 1039 13572677 14102011403