141020131101 has 4 divisors (see below), whose sum is σ = 188026841472. Its totient is φ = 94013420732.

The previous prime is 141020131069. The next prime is 141020131121. The reversal of 141020131101 is 101131020141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 101131020141 = 3 ⋅33710340047.

It is a cyclic number.

It is not a de Polignac number, because 141020131101 - 2⁵ = 141020131069 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141020131121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23503355181 + ... + 23503355186.

It is an arithmetic number, because the mean of its divisors is an integer number (47006710368).

Almost surely, 2^141020131101 is an apocalyptic number.

It is an amenable number.

141020131101 is a deficient number, since it is larger than the sum of its proper divisors (47006710371).

141020131101 is an equidigital number, since it uses as much as digits as its factorization.

141020131101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47006710370.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 141020131101 its reverse (101131020141), we get a palindrome (242151151242).

The spelling of 141020131101 in words is "one hundred forty-one billion, twenty million, one hundred thirty-one thousand, one hundred one".