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141020203 is a prime number
BaseRepresentation
bin10000110011111…
…00110000101011
3100211100120100111
420121330300223
5242100121303
621554315151
73331436422
oct1031746053
9324316314
10141020203
1172669625
123b288ab7
13232a680c
1414a2c2b9
15c5a8b6d
hex867cc2b

141020203 has 2 divisors, whose sum is σ = 141020204. Its totient is φ = 141020202.

The previous prime is 141020179. The next prime is 141020213. The reversal of 141020203 is 302020141.

141020203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (302020141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141020203 - 25 = 141020171 is a prime.

It is a super-2 number, since 2×1410202032 = 39773395308322418, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (141020213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70510101 + 70510102.

It is an arithmetic number, because the mean of its divisors is an integer number (70510102).

Almost surely, 2141020203 is an apocalyptic number.

141020203 is a deficient number, since it is larger than the sum of its proper divisors (1).

141020203 is an equidigital number, since it uses as much as digits as its factorization.

141020203 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 141020203 is about 11875.1927563303. The cubic root of 141020203 is about 520.5076440499.

Adding to 141020203 its reverse (302020141), we get a palindrome (443040344).

The spelling of 141020203 in words is "one hundred forty-one million, twenty thousand, two hundred three".