14102040112111 has 4 divisors (see below), whose sum is σ = 16116617270992. Its totient is φ = 12087462953232.

The previous prime is 14102040112103. The next prime is 14102040112169. The reversal of 14102040112111 is 11121104020141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14102040112111 - 2³ = 14102040112103 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14102040113111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1007288579430 + ... + 1007288579443.

It is an arithmetic number, because the mean of its divisors is an integer number (4029154317748).

Almost surely, 2^{14102040112111} is an apocalyptic number.

14102040112111 is a deficient number, since it is larger than the sum of its proper divisors (2014577158881).

14102040112111 is an equidigital number, since it uses as much as digits as its factorization.

14102040112111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2014577158880.

The product of its (nonzero) digits is 64, while the sum is 19.

Adding to 14102040112111 its reverse (11121104020141), we get a palindrome (25223144132252).

The spelling of 14102040112111 in words is "fourteen trillion, one hundred two billion, forty million, one hundred twelve thousand, one hundred eleven".