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14102041121 = 73509957397
BaseRepresentation
bin11010010001000110…
…00001001000100001
31100101210110220200022
431020203001020201
5212340110303441
610251155403225
71006314241340
oct151043011041
940353426608
1014102041121
115a87264243
1228968b3515
1314397b873c
1497ac79b57
1557808c84b
hex3488c1221

14102041121 has 8 divisors (see below), whose sum is σ = 16117358400. Its totient is φ = 12086908848.

The previous prime is 14102041117. The next prime is 14102041123. The reversal of 14102041121 is 12114020141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14102041121 - 22 = 14102041117 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14102041121.

It is not an unprimeable number, because it can be changed into a prime (14102041123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 216995 + ... + 274391.

It is an arithmetic number, because the mean of its divisors is an integer number (2014669800).

Almost surely, 214102041121 is an apocalyptic number.

It is an amenable number.

14102041121 is a deficient number, since it is larger than the sum of its proper divisors (2015317279).

14102041121 is an equidigital number, since it uses as much as digits as its factorization.

14102041121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92503.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 14102041121 its reverse (12114020141), we get a palindrome (26216061262).

The spelling of 14102041121 in words is "fourteen billion, one hundred two million, forty-one thousand, one hundred twenty-one".

Divisors: 1 7 35099 57397 245693 401779 2014577303 14102041121