14102041122 has 96 divisors (see below), whose sum is σ = 33571976256. Its totient is φ = 4251657600.

The previous prime is 14102041117. The next prime is 14102041123. The reversal of 14102041122 is 22114020141.

14102041122 is digitally balanced in base 5, because in such base it contains all the possibile digits an equal number of times.

It is a super-3 number, since 3×14102041122³ (a number of 31 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 14102041095 and 14102041104.

It is not an unprimeable number, because it can be changed into a prime (14102041123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4037797 + ... + 4041287.

It is an arithmetic number, because the mean of its divisors is an integer number (349708086).

Almost surely, 2^14102041122 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14102041122, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16785988128).

14102041122 is an abundant number, since it is smaller than the sum of its proper divisors (19469935134).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14102041122 is a wasteful number, since it uses less digits than its factorization.

14102041122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3856 (or 3853 counting only the distinct ones).

The product of its (nonzero) digits is 128, while the sum is 18.

Adding to 14102041122 its reverse (22114020141), we get a palindrome (36216061263).

The spelling of 14102041122 in words is "fourteen billion, one hundred two million, forty-one thousand, one hundred twenty-two".