14103111422131 has 4 divisors (see below), whose sum is σ = 14369207864112. Its totient is φ = 13837014980152.

The previous prime is 14103111422119. The next prime is 14103111422209. The reversal of 14103111422131 is 13122411130141.

14103111422131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14103111422131 - 2³⁷ = 13965672468659 is a prime.

It is a super-2 number, since 2×14103111422131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14103111422096 and 14103111422105.

It is not an unprimeable number, because it can be changed into a prime (14103111422531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133048220911 + ... + 133048221016.

It is an arithmetic number, because the mean of its divisors is an integer number (3592301966028).

Almost surely, 2^{14103111422131} is an apocalyptic number.

14103111422131 is a deficient number, since it is larger than the sum of its proper divisors (266096441981).

14103111422131 is an equidigital number, since it uses as much as digits as its factorization.

14103111422131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 266096441980.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 14103111422131 its reverse (13122411130141), we get a palindrome (27225522552272).

The spelling of 14103111422131 in words is "fourteen trillion, one hundred three billion, one hundred eleven million, four hundred twenty-two thousand, one hundred thirty-one".