Base | Representation |
---|---|
bin | 1000001101011000011… |
… | …1010101010110000011 |
3 | 111111000201002021101122 |
4 | 2003112013111112003 |
5 | 4302312441401011 |
6 | 144442220022455 |
7 | 13121612264453 |
oct | 2032607252603 |
9 | 444021067348 |
10 | 141031200131 |
11 | 548a1488058 |
12 | 233bb091a2b |
13 | 103b74044a3 |
14 | 6b7c57bd63 |
15 | 3a065173db |
hex | 20d61d5583 |
141031200131 has 2 divisors, whose sum is σ = 141031200132. Its totient is φ = 141031200130.
The previous prime is 141031200127. The next prime is 141031200139. The reversal of 141031200131 is 131002130141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141031200131 - 22 = 141031200127 is a prime.
It is a super-2 number, since 2×1410312001312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (141031200139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70515600065 + 70515600066.
It is an arithmetic number, because the mean of its divisors is an integer number (70515600066).
Almost surely, 2141031200131 is an apocalyptic number.
141031200131 is a deficient number, since it is larger than the sum of its proper divisors (1).
141031200131 is an equidigital number, since it uses as much as digits as its factorization.
141031200131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 141031200131 its reverse (131002130141), we get a palindrome (272033330272).
The spelling of 141031200131 in words is "one hundred forty-one billion, thirty-one million, two hundred thousand, one hundred thirty-one".
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