Base | Representation |
---|---|
bin | 11010010001001110… |
… | …11100001100010111 |
3 | 1100101212122211002120 |
4 | 31020213130030113 |
5 | 212340404404120 |
6 | 10251240311023 |
7 | 1006330140504 |
oct | 151047341427 |
9 | 40355584076 |
10 | 14103200535 |
11 | 5a87986336 |
12 | 2897172473 |
13 | 1439b03398 |
14 | 97b09c4ab |
15 | 57821b140 |
hex | 3489dc317 |
14103200535 has 16 divisors (see below), whose sum is σ = 22689794400. Its totient is φ = 7480149120.
The previous prime is 14103200483. The next prime is 14103200537. The reversal of 14103200535 is 53500230141.
14103200535 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 14103200535 - 27 = 14103200407 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14103200537) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2594560 + ... + 2599989.
It is an arithmetic number, because the mean of its divisors is an integer number (1418112150).
Almost surely, 214103200535 is an apocalyptic number.
14103200535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14103200535 is a deficient number, since it is larger than the sum of its proper divisors (8586593865).
14103200535 is a wasteful number, since it uses less digits than its factorization.
14103200535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5194738.
The product of its (nonzero) digits is 1800, while the sum is 24.
Adding to 14103200535 its reverse (53500230141), we get a palindrome (67603430676).
The spelling of 14103200535 in words is "fourteen billion, one hundred three million, two hundred thousand, five hundred thirty-five".
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