Base | Representation |
---|---|
bin | 1100110100111110101111… |
… | …0001010111111001000010 |
3 | 1211221100202020021202100021 |
4 | 3031033223301113321002 |
5 | 3322041133301041232 |
6 | 45555235150044054 |
7 | 2654001345165532 |
oct | 315175361277102 |
9 | 54840666252307 |
10 | 14104333221442 |
11 | 454868344a132 |
12 | 16b96207a962a |
13 | 7b4057415239 |
14 | 36a920bc34c2 |
15 | 196d45780397 |
hex | cd3ebc57e42 |
14104333221442 has 4 divisors (see below), whose sum is σ = 21156499832166. Its totient is φ = 7052166610720.
The previous prime is 14104333221413. The next prime is 14104333221457. The reversal of 14104333221442 is 24412233340141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12065209197001 + 2039124024441 = 3473501^2 + 1427979^2 .
It is a junction number, because it is equal to n+sod(n) for n = 14104333221398 and 14104333221407.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3526083305359 + ... + 3526083305362.
Almost surely, 214104333221442 is an apocalyptic number.
14104333221442 is a deficient number, since it is larger than the sum of its proper divisors (7052166610724).
14104333221442 is an equidigital number, since it uses as much as digits as its factorization.
14104333221442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7052166610723.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 14104333221442 its reverse (24412233340141), we get a palindrome (38516566561583).
The spelling of 14104333221442 in words is "fourteen trillion, one hundred four billion, three hundred thirty-three million, two hundred twenty-one thousand, four hundred forty-two".
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