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14107739448433 is a prime number
BaseRepresentation
bin1100110101001011011011…
…0011000110010001110001
31211221200112121201000100111
43031102312303012101301
53322120122244322213
650001001145221321
72654151635506501
oct315226663062161
954850477630314
1014107739448433
11454a071148964
1216ba211491841
137b447b00b477
1436ab65331a01
15196e94817a3d
hexcd4b6cc6471

14107739448433 has 2 divisors, whose sum is σ = 14107739448434. Its totient is φ = 14107739448432.

The previous prime is 14107739448367. The next prime is 14107739448463. The reversal of 14107739448433 is 33484493770141.

14107739448433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13883880827664 + 223858620769 = 3726108^2 + 473137^2 .

It is an emirp because it is prime and its reverse (33484493770141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14107739448433 - 213 = 14107739440241 is a prime.

It is not a weakly prime, because it can be changed into another prime (14107739448463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7053869724216 + 7053869724217.

It is an arithmetic number, because the mean of its divisors is an integer number (7053869724217).

Almost surely, 214107739448433 is an apocalyptic number.

It is an amenable number.

14107739448433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14107739448433 is an equidigital number, since it uses as much as digits as its factorization.

14107739448433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24385536, while the sum is 58.

The spelling of 14107739448433 in words is "fourteen trillion, one hundred seven billion, seven hundred thirty-nine million, four hundred forty-eight thousand, four hundred thirty-three".