1411000101211 has 2 divisors, whose sum is σ = 1411000101212. Its totient is φ = 1411000101210.

The previous prime is 1411000101197. The next prime is 1411000101221. The reversal of 1411000101211 is 1121010001141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1411000101211 - 2⁵ = 1411000101179 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1411000101191 and 1411000101200.

It is not a weakly prime, because it can be changed into another prime (1411000101221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705500050605 + 705500050606.

It is an arithmetic number, because the mean of its divisors is an integer number (705500050606).

Almost surely, 2^{1411000101211} is an apocalyptic number.

1411000101211 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411000101211 is an equidigital number, since it uses as much as digits as its factorization.

1411000101211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 1411000101211 its reverse (1121010001141), we get a palindrome (2532010102352).

The spelling of 1411000101211 in words is "one trillion, four hundred eleven billion, one hundred one thousand, two hundred eleven".