Base | Representation |
---|---|
bin | 1100110101010011110110… |
… | …0110101111101010100111 |
3 | 1211221220101020110120000202 |
4 | 3031110331212233222213 |
5 | 3322134240242243442 |
6 | 50002013421101115 |
7 | 2654261660513624 |
oct | 315247546575247 |
9 | 54856336416022 |
10 | 14110001134247 |
11 | 455002187a997 |
12 | 16ba7429b779b |
13 | 7b474b75a1b5 |
14 | 36acdb86934b |
15 | 19707816bc32 |
hex | cd53d9afaa7 |
14110001134247 has 8 divisors (see below), whose sum is σ = 14116302204480. Its totient is φ = 14103701303040.
The previous prime is 14110001134237. The next prime is 14110001134297. The reversal of 14110001134247 is 74243110001141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14110001134247 - 222 = 14109996939943 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14110001134237) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22856579 + ... + 23465787.
It is an arithmetic number, because the mean of its divisors is an integer number (1764537775560).
Almost surely, 214110001134247 is an apocalyptic number.
14110001134247 is a deficient number, since it is larger than the sum of its proper divisors (6301070233).
14110001134247 is an equidigital number, since it uses as much as digits as its factorization.
14110001134247 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 619513.
The product of its (nonzero) digits is 2688, while the sum is 29.
Adding to 14110001134247 its reverse (74243110001141), we get a palindrome (88353111135388).
The spelling of 14110001134247 in words is "fourteen trillion, one hundred ten billion, one million, one hundred thirty-four thousand, two hundred forty-seven".
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